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What is an equation of the line perpendicular to y=-x-2 and through (-2,4)

User Bryen
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1 Answer

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Let
k:y=m_1x+b_1 and
l:y=m_2x+b_2


l\ \perp\ k\iff m_1m_2=-1\to m_2=-(1)/(m_1)

We have


y=-x-2\to m_1=-1

Therefore


m_2=-(1)/(-1)=1

We have the equation of a line:


y=-1x+b\to y=-x+b

Put the coordinates of the point (-2, 4) to the equation of a line:


4=-(-2)+b


4=2+b subtract 2 from both sides


2=b\to b=2

Answer: y = -x + 2

User Sumit M Asok
by
8.6k points

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