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9/20m^4+100m^3-2m^2/3m^2+16m+5 =

9/20m^4+100m^3-2m^2/3m^2+16m+5 =-example-1
User Bill Keese
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1 Answer

3 votes

Factor out the common term 200m^3

9/20m^3(m + 5) - 2m^2(3m^2 + 16m + 5

Split the second term in 3m^2 + 16m + 5 into these two terms

9/20m^3(m + 5) - 2m^2/3m^2 + 15m + m + 5

Factor out the common terms in the two terms, then in the last two terms;

9/20m^3(m + 5) - 2m^2/3m(m + 5) + (m + 5)

Factor out the common term m + 5

9/20m^3(m + 5) - 2m^2/(m + 5)(3m + 1)

Cross multiply

9(3m + 1) - (2 × 20)m^2m^3/20m^3(m + 5)(3m + 1)

Simplify 2 × 20 to 40

9(3m + 1) - 40m^2m^3/20m^3(m + 5)(3m + 1)

Use the Product Rule: x^ax^b = x^a + b

9(3m + 1) - 40m^2 + 3/ 20m^3(m + 5)(3m + 1)

Simplify 2 + 3 to 5

9(3m + 1) - 40m^5/20m^3(m + 5)(3m + 1)

Expand


(27m+9-40m^5)/(20m^3(m+5)(3m+1))

User Kelvin Schoofs
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