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ABC~RST with m<A=6x+17, m<3x+9, and m<C=37. Find the measure of R

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Answer:

Hence, m∠R=95°.

Explanation:

We are given that ΔABC is similar to the ΔRST i.e. ΔABC~ΔRST.

Aslo m∠A=6x+17, m∠B=3x+9, and m∠C=37

We know that sum of all the angles of a triangle is 180°.

⇒ ∠A+∠B+∠C=180

⇒ 6x+17+3x+9+37=180

⇒ 9x+63=180 (As 6x+3x=9x and 17+9+37=63)

⇒ 9x=180-63

⇒9x=117

⇒ x=13. (on dividing both side by 9)

Hence m∠A=6x+17=6×13+17=95°

m∠B=3x+9=3×13+9=48°

m∠C=37°

Also as ΔABC~ΔRST so this implies m∠R=m∠A=95°

Hence, m∠R=95°.



User Dhamo Dharan
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