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If the radius of the base of the cone is 8/3 units and the height is 12 units, what is the volume?

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6 votes

Answer:

89.32

Explanation:

The volume of a cone with radius 8/3 and height 12 is


V= (1)/(3)\pi r^2 h=  (1)/(3)\pi ((8)/(3)^2)(12) =  (1)/(3)\pi ((64)/(9))(12)= (1*64*12)/(3*9)\pi = (256)/(9) \pi = 89.32.

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