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If the radius of the base of the cone is 8/3 units and the height is 12 units, what is the volume?

User Sameera K
by
8.1k points

1 Answer

5 votes

Answer:

256/9 * pi units ^3

or approximately

89.3608577021096743 units^3

Explanation:

V = 1/3 pi r^2 h

where r is the radius and h is the height

V = 1/3 * pi * (8/3) ^2 * 12

= 1/3 * pi * 64/9 * 12

256/9 * pi units ^3

or approximately

89.3608577021096743 units^3

User Cody Covey
by
8.3k points

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