Question

How do I solve this equation

Answer 1

Use the Quadratic Formula.

In general, given ax^2 + bx + c = 0, there are two solutions that exist, where;

x = -b + √b^2 - 4ac/2a , -b √b^2 - 4ac/2a

In this case, a = 1, b = -5, and c = -7

x = 5 + √(-5)^2 - 4 * -7/2 , 5 - √(-5)^2 - 4 * -7/2

Simplify

`x = (5+√(53) )/(2) , (5-√(23) )/(2)`