For this case we must indicate which of the options given is a factor of the following polynomial:
![4c ^ 3-2c ^ 2-6c](https://img.qammunity.org/2020/formulas/mathematics/high-school/8rt4jfmlio4xab68qkqq8mdzmz6gzgq6rm.png)
If we take common factor of the terms we have:
![2c (2c ^ 2-c-3)](https://img.qammunity.org/2020/formulas/mathematics/high-school/5qlqh7qwdbv5nt3prxbxrfy5jteac7tcbo.png)
Within the parenthesis we have
, then:
The term of the medium is rewritten as a sum of two terms, whose multiplication is
and the sum is -1. These numbers are:
-3 and 2
![(-3) (2) = - 6\\-3 + 2 = -1](https://img.qammunity.org/2020/formulas/mathematics/high-school/sixqad0tum939ijtdwdnt6bhxvdtmgsvnq.png)
So;
![2c ^ 2-c-3 =\\2c ^ 2-3c + 2c-3](https://img.qammunity.org/2020/formulas/mathematics/high-school/s00naa84hw29y6jv0bcwbifvawvrp8w1kb.png)
Factoring for each group we have:
![c (2c-3) +1 (2c-3)](https://img.qammunity.org/2020/formulas/mathematics/high-school/nebfeyotx9dxshzxttqs7a7op6nriawjp7.png)
This is equivalent to:
![(c + 1) (2c-3)](https://img.qammunity.org/2020/formulas/mathematics/high-school/376uxtj87cxzilnlxkeq6cs9erllj1mb7m.png)
Thus,
![2c ^ 2-c-3 = (c + 1) (2c-3)](https://img.qammunity.org/2020/formulas/mathematics/high-school/rxyo1438xlwsbo5a4ezx8s26gub8ixw2cv.png)
Then,
![4c ^ 3-2c ^ 2-6c = 2c ((c + 1) (2c-3))](https://img.qammunity.org/2020/formulas/mathematics/high-school/18w61zyj7f6bchwyxchz2em44xivhqmw11.png)
Thus, a factor of the polynomial is
![c + 1](https://img.qammunity.org/2020/formulas/mathematics/high-school/8vesd5lthhgv7mwfm76pucvforzb4oalhz.png)
Answer:
Option A