Answer:
A
Explanation:
For factoring, if we can ever right a factor as
and another as
with a MINUS in between them, then the technique of "difference in two squares" is perfect!
From the problem shown, we can actually do this (shown below):
![x^2-25\\=(x)^2-(5)^2](https://img.qammunity.org/2020/formulas/mathematics/high-school/54qjhut3h02ah08whenbe1depv87r4mrws.png)
The rule is
![a^2-b^2=(a+b)(a-b)](https://img.qammunity.org/2020/formulas/mathematics/high-school/mpelom9ylwg2nq2fvp5mq21fxoygocnfpy.png)
Thus the problem reduces to:
![(x)^2-(5)^2\\=(x+5)(x-5)](https://img.qammunity.org/2020/formulas/mathematics/high-school/21to323pe64x8ybmp1wuwi2hw1d8mmaiq6.png)
We have use "difference of two squares" here, hence answer choice A is right.