Question

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Answer 1

`sin\theta=(1)/(2)`

=============

Given

• 
  `cos \theta=(√(3) )/(2)`

To find

• The value of
  `sin\theta`

Solution

Use identity
`sin^2\theta+cos^2\theta=1` :

• 
  `sin^2\theta=1-cos^2\theta`
• 
  `sin^2\theta=1-((√(3) )/(2) )^2`
• 
  `sin^2\theta=1-\frac{{3} }{4}`
• 
  `sin^2\theta=\frac{{1} }{4}`
• 
  `sin\theta=\sqrt{\frac{{1} }{4} }`
• 
  `sin\theta={\frac{{1} }{2} }`