Question

The point-slope form of the equation of the line that passes through (4, -3) and (12, 1) is12). What is the standard form of the equation for this line?

Answer 1

The point slope equation be
`y = (1x)/(2)-5` .

Explanation:

The point slope equation of the line is given by .

`(y-y_(1))=m (x-x_(1))`

Where m is the slope .

`m =(y_(2)-y_(1))/(x_(2)-x_(1))`

`m =(4)/(8)`

`m = (1)/(2)`

As given

The point-slope form of the equation of the line that passes through (4, -3) and (12, 1) is
`(1)/(2)` .

Putting the values in the point slope equation .

`(y-(-3))=(1)/(2)(x-4)`

`2* (y+3)=x-4`

2y + 6 = x - 4

2y = x - 4 - 6

2y = x -10

`y = (1x)/(2)-(10)/(2)`

`y = (1x)/(2)-5`

Therefore the point slope equation be
`y = (1x)/(2)-5` .