ln is an operation only for numbers greater than zero. Like this we know that (-x+3/2) must be greater than zero. Since 2 is a positive constant, we only need to make sure the term -x+3 is also positive and different than zero.
We can use this inequality to solve that problem:
![- x + 3 > 0 \\](https://img.qammunity.org/2020/formulas/mathematics/high-school/isictlqn3m5tlkkz3gncl6qsb4mofi4314.png)
Put the 3 in the other side of the inequality like -3:
![- x > - 3](https://img.qammunity.org/2020/formulas/mathematics/high-school/h4rb9s1qulcilvinokxdgqe9wjfx6zyyle.png)
Now change the negative symbol, changing the inequality symbol as well
![x < 3](https://img.qammunity.org/2020/formulas/mathematics/high-school/1j8miinze4sb8oaov5t6q3mpyllq9offip.png)
This means the domain of the function are all the numbers less than 3:
The answer is x<3