Question

An atom undergoes radioactive decay according to this equation: 129/54 Xe + 0/-1e What was the identity of the parent atom?

Answer 1

Correct Answer is (D)

Step-by-step explanation:

Correct answer on Plato too :)

Answer 2

Answer: Option (D) is the correct answer.

Step-by-step explanation:

Parent atom is the atom which undergoes radioactive decay in a nuclear reaction. After the decay, this parent atom results in the formation of different products.

The given radioactive decay reaction will be as follows.

`^(129)_(53)I \rightarrow ^(129)_(54)Xe + ^(0)_(-1)e`

Here, beta particle is emitted along with the formation of
`^(129)_(54)X`.

Thus, we can conclude that in this reaction the parent atom is
`^(129)_(53)I`.