Question

Based on the polynomial remainder theorem, what is the value of the function when x = 4?

f(x)=x^4−2x^3+5x^2−20x−4

What does f(4) =

Answer 1

f(4) = 124

Explanation:

To find f(4), substitute 4 into x and simplify.

`f(x)=x^4 - 2x^3 +5x^2 -20x -4\\f(4) = 4^4-2*4^3+5*4^2-20*4-4\\f(4) = 256 -2*64 + 5*16 -80-4\\f(4) = 256 -128+80-80-4\\f(4) = 128+80-80-4\\f(4) = 208 -80 -4\\f(4) = 128 - 4\\f(4) = 124`