Answer: Investment in Account A = 1750
Investment in Account B = 3250
Explanation:
Here, the total investment = 5000
Let the amount invested in account A = x
Therefore, the amount invested in account B = 5000-x
In Account A, rate of interest = 4% per year
Thus, interest earn in one year
=
![(x* 4* 1)/(100)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/jd6asul53mvgygezh00isvk5wgzmtp3a2u.png)
=
![(4x)/(100)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/y6chp3barintbsu11ud4ldd4ygv7b1p883.png)
Now, The interest in account B = 2% per year
Thus, the interest earn in one year
=
![((5000-x)* 2* 1)/(100)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/kqagns62mnrgia17avkp010gpfgt42wmgy.png)
=
![(2(5000-x))/(100)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ixsoyifgn0azt8j9xd0s21odherym9kcpx.png)
Therefore, total interest =
![(4x)/(100)+(2(5000-x))/(100)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/y1zst2gp1ygnx3ccmiaziawk0n0bexagzh.png)
⇒
![(4x)/(100)+(2(5000-x))/(100)=135](https://img.qammunity.org/2020/formulas/mathematics/middle-school/w8uldhh9851zjb5wup5q1c7x584iuc3ack.png)
⇒
![(4x)/(100)+(10000-2x)/(100)=135](https://img.qammunity.org/2020/formulas/mathematics/middle-school/uk7ijvv85jem10jwqlo15nv0nr422ar4gs.png)
⇒
![(4x+10000-2x)/(100)=135](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ct22jgb21e6e1ts5ezpqmrr8wr7vhhgdyr.png)
⇒
![(2x+10000)/(100)=135](https://img.qammunity.org/2020/formulas/mathematics/middle-school/uyrdiojfssu62ucxj9uvy70cbzsw1uptwy.png)
⇒
![2x+10000=13500](https://img.qammunity.org/2020/formulas/mathematics/middle-school/geaeb7sghzinaoa8dtgscgs9uxgyzp2dwy.png)
⇒
![2x=3500](https://img.qammunity.org/2020/formulas/mathematics/middle-school/13suhy9wfrpblugqa2ecgponhvtb9ptdxa.png)
⇒
![x=1750](https://img.qammunity.org/2020/formulas/mathematics/middle-school/jcqhdycqm45fqn9ruzn57k11tsciazvjd0.png)
Therefore, investment in account A = $1750
While, in account B = 5000-1750 = $3250