Question

9.4 moles of c12h22o11 = ______ atoms o

Answer 1

6.3 × 10²⁵ atoms of O

Explanation:

`\text{moles of O} = \text{9.4 mol C$_(12)$H$_(22)$O$_(11)$} *  \frac{ 11 \text{ mol O }}{\text{1 mol C$_(12)$H$_(22)$O$_(11)$}} = \text{103.4 mol O}`

`\text{Atoms of O} =\text{103.4 mol O} * \frac{ 6.022 * 10^(23) \text{ atoms O}}{\text{1 mol O}}= 6.3 * 10^(25) \text{ atoms O}`

Thus, 9.4 mol of C₁₂H₂₂O₁₁ contains 6.3 × 10²⁵ atoms of O.