In triangle ABC
tanθ = BC/AB
tanθ = x/2
taking derivative both side relative to "t"
sec²θ (dθ/dt) = (0.5) (dx/dt)
sec²θ w = (0.5) v eq-1
when x = 4 ,
tanθ = 4/2
θ = tan⁻¹ (2) = 63.4 deg
using eq-1
sec²θ w = (0.5) v
sec²63.4 (3) (2pi/60) = (0.5) v
v = 3.13 m/s