Answer:
P(heads appears on only the last toss) =
![(1)/(8)](https://img.qammunity.org/2020/formulas/mathematics/college/oishxf3znbtm7sgua7hx3bnp2grk4mwmno.png)
Explanation:
A fair coin is tossed 3 times in a row.
When a coin is tossed we get a tail or head T or H
The possible outcomes of 3 coins are
T T T , H H H , T H H, H T H, H H T, H T T , T H T, T T H
So total of 8 possible outcomes
heads appears on only the last toss , first and second toss should be tail
So its T T H. Only one possibility
Probability(any event) = number of outcomes / total outcomes
P(heads appears on only the last toss) =
![(1)/(8)](https://img.qammunity.org/2020/formulas/mathematics/college/oishxf3znbtm7sgua7hx3bnp2grk4mwmno.png)