Question

A ball is dropped from a height of 10 meters. Each time it bounces, it reaches 50 percent of its previous height. The total vertical distance down the ball has traveled when it hits the ground the fifth time is meters.

Answer 1

By the fifth bounce, it would reach 31.25 centimeters

Explanation:

10/2=5

5/2=2.5

2.5/2=1.25

1.25/2=0.625

0.625/2=0.3125

0.3125 meters multiplied by 100(to get centimeters) = 31.25 centimeters

I hope this was helpful <3

Answer 2

28.75 m

Explanation:

a) First Fall d=10 m ( first Hit)

b) Second fall

height = 5 m

height lost = 5 m (second hit)

Total = 10 m

c) Third Fall

Height = 2.50 m

height lost = 2.50 m (third hit)

Total distance = 5 m

d) forth Fall

Height = 1.25 m

Height lost = 1.25 m (forth hit)

Total distance = 2.50 m

e) fifth Fall

Height = 0.625 m

Height Lost = 0.625 m (fifth hit)

Total Distance = 10+5*2+2.50*2+1.25*2+0.625*2

=10+10+5+2.50+1.25

=20+7.50+1.25

=27.50+1.25

=28.75 m

Answer