Question

Pls help. This is about heat. I got the answer, just need the working

Answer 1

See below

Step-by-step explanation:

You have to heat the calorimeter to 100 C from 20 C

this will take .20 kg * 390 j /kg-C * 80 C = 6240 j

You have to heat the mass of water to boiling point (100 C ) from 20C

this will take

.50 kg * 4182 j/kg-C * 80 = 167,280 j

AND you have to add enough heat to boil off .03 kg of water:

.03 kg * (2260000 j/kg-C ) = 67,800 j

Power = joules / sec = (6240 + 167280 + 67800) / 274.8 = 878 watts

Your answer may differ just a bit for slightly different or rounded values of specific heat or heat of fusion for water .....