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What is the concentration (M) of sodium ions in 4.57 L of a 0.398 M Na3PO4 solution?
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What is the concentration (M) of sodium ions in 4.57 L of a 0.398 M Na3PO4 solution?

User Pratik Vekariya
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0.398=mol/4.57L. mol= 1.818. 1.818*3=5.456. 5.456/(4.57L)=1.19 M

User Notsoux
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