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Find the zeros 3x^2+4x+2
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1 Answer

5 votes

Answer:

x = 0 or x = -4/3

Explanation:

Solve for x over the real numbers:

x (3 x + 4) = 0

Split into two equations:

x = 0 or 3 x + 4 = 0

Subtract 4 from both sides:

x = 0 or 3 x = -4

Divide both sides by 3:

Answer: x = 0 or x = -4/3

User Dhahn
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