Determine the slope of a line that is perpendicular to the equation 3x + 6y =18

Question

asked Feb 27, 2023 1.6k views

2 Answers

V G · Answer 1 · 2023-02-27T22:52:57+0000

$\Large\maltese\underline{\textsf{A. What is Asked}}$

Determine the slope of the line perpendicular to 3x+6y=18

$\Large\maltese\underline{\textsf{B. This problem has been solved!}}$

$\bf{(3)/(6)x+(6)/(6)y=(18)/(6)$ | dividing the ENTIRE equation by 6, to make it easier to write in y=mx+b form

$\bf{(1)/(2)x+y=3}$ | subtract 1/2 x

$\bf{y=-(1)/(2)x+3$ .

$\cline{1-2}$

Now, perpendicular lines' slopes are opposite inverses of each other.

The opposite inverse of -1/2 is

= 2

$\cline{1-2}$

$\bf{Result:}$

$\bf{=2}$

$\LARGE\boxed{\bf{aesthetics\\ot1\theta l}}$

Muhammed Albarmavi · Answer 2 · 2023-03-05T00:30:42+0000

Rewriting the equation of the given line in slope-intercept form,

$3x+6y=18\\\\x+2y=6\\\\2y=-x+6\\\\y=-(1)/(2)x+3$

This means the slope of the given line is -1/2.

As perpendicular lines have slopes that are negative reciprocals, the answer is 2.