For this case we have a rectangle triangle where the hypotenuse is 10 feet and the base is 6 feet. It is asked to find the angle that is formed between the base of the triangle and the hypotenuse, which we will call "x".
We know that:
![cosine (x) = \frac {leg \ adjacent} {hypotenuse}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/u1vatk44gjb2s7lp0hy5tdxqih1klu5eqk.png)
Substituting we have:
![cosine (x) = \frac {6} {10}\\cosine (x) = 0.6](https://img.qammunity.org/2020/formulas/mathematics/middle-school/l8mc8zb7kios4a8ohc4kf2p2dgj8qz7y1t.png)
![x = cosine\ arc\ (0.6)\\x = 53.1301024](https://img.qammunity.org/2020/formulas/mathematics/middle-school/f90y25oonmakmyol983w6o567patwelhcs.png)
Rounding off we have:
![x = 53.1](https://img.qammunity.org/2020/formulas/mathematics/middle-school/6a9z4s7s2csruducg1sxao9p2vbzzaz3pm.png)
Answer:
53.1 degrees
Option C