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Find the sum of the first 4 terms of the series.

2-8+32-128+.....
a.
–101
b.
–103
c.
–102
d.
–104


Please select the best answer from the choices provided

a) A
b) B
c) C
d) D

User Jlandercy
by
5.0k points

1 Answer

3 votes

Answer:

Answer: Option c. (-102) is the sum of first four terms of the sequence.

Explanation:

In the sequence 2-8+32-128..... we know number of terms n=4

First term A(1)=2

Ratio of the terms r = (-4)

And we have to calculate the sum of four terms

We know the formula for this question is


\sum_(K=0)^(n-1)A(1)r^(k)=A(1)((1-r^(n))/(1-r))


\sum_(K=0)^(4-1)A(1)r^(k)=A(1)((1-(-4)^(4))/(1-(-4)))


Sum=2((1-(4)^(4))/(1+4))
= 2((1-266)/(5))   = 2((-255)/(5))   =2(-51)

Sum of first 4 terms is (-102)


User Raky
by
5.5k points