Question

Please help meee with my math i am so confused!!! Thank youuuu

Answer 1

Explanation:

x decreases w/o bound, so x becomes a very large -ve no.

f(x)=5^(x-1) becomes 5^(large -ve no.) which will be almost zero

x increases w/o bound, so x becomes a very large +ve no.

f(x)=5^(x-1) becomes 5^(large +ve no.) which will keep increasing w/o bound

if u provide wat the choices are from ur Q in comments, i will pick the right one 4 u

Answer 2

As x→-∞ f(x) →0

As x→∞ f(x) →∞

Explanation:

f(x) = 5^(x-1)

as x approaches negative infinity

f(x) = 5^ - ∞

1/ 5^∞

1/ big number

0

As x→-∞ f(x) →0

as x approaches infinity

f(x) = 5^ ∞

5^∞

big number

As x→∞ f(x) →∞