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Julian fully simplifies this polynomial and then writes it in standard form.

4x2y2 – 2y4 – 8xy3 + 9x3y + 6y4 – 2xy3 – 3x4 + x2y2

If Julian wrote the last term as –3x4, which must be the first term of his polynomial in standard form?

a) 4y4
b) 6y4
c) –2xy3
d) –10xy3

User Bacon
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1 Answer

4 votes

Answer:

4y^4

Explanation:


4x^2y^2 - 2y^4 - 8xy^3 + 9x^3y + 6y^4 - 2xy^3 - 3x^4 + x^2y^2

Last term is -3x^4

This means x term is increasing and it ends at x^4

we arrange the terms in order


6y^4- 2y^4 - 8xy^3 - 2xy^3 +4x^2y^2+ x^2y^2 + 9x^3y-3x^4

now we combine like terms


4y^4 - 10xy^3 +5x^2y^2 + 9x^3y -3x^4

So first term is 4y^4

User Alift
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