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Find an equation for a line with a slope of 3/5, passing through (2,-4)

User Ramaralo
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\bf (\stackrel{x_1}{2}~,~\stackrel{y_1}{-4}) ~\hspace{10em} slope = m\implies \cfrac{3}{5} \\\\\\ \begin{array} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-(-4)=\cfrac{3}{5}(x-2) \implies y+4=\cfrac{3}{5}x-\cfrac{6}{5} \\\\\\ y=\cfrac{3}{5}x-\cfrac{6}{5}-4\implies y=\cfrac{3}{5}x-\cfrac{26}{5}

User Croisharp
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