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Y+3z+2y-z evaluate if y=3 and z=6
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Y+3z+2y-z evaluate if y=3 and z=6

User Angeliki
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1 Answer

4 votes

Answer:

21

Explanation:

y+3x+2y-z

3+3(6)+2(3)-6 First fill in Y and Z

3+18+6-6 Multiply 3x6 is 18 and 2x3 is 6 so fill that in

21+6-6 add 18+3 is 21+6 is 27

27-6 Subtract 27-6 is 21

=21 Answer

User Cgotberg
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