Question

Expressed in simplified radical form what is the value of √r-√16r when r=2

Answer 1

- 3
`√(2)`

Explanation:

using the rule of radicals

`√(a)` ×
`√(b)` ⇔
`√(ab)`

simplifying
`√(16r)` when r = 2

=
`√(32)`

=
`√(16(2))`

=
`√(16)` ×
`√(2)` = 4
`√(2)`, hence

`√(2)` - 4
`√(2)` = - 3
`√(2)`