Question

What is the simplest radical form of the expression?

(x3y4)23




x4y6x√

xy2x2‾‾√3

x2y2y2‾‾√3

x4y3y√

Answer 1

the answer is he answer is c

Explanation:

Answer 2

Answer: The answer is
`x^2y^2\sqrt[3]{y^2}.`

Explanation: The given expression is as follows

`(x^3y^4)^{(2)/(3)}.`

We are given to convert the above expression to the simplest radical form. For that, first we need to evaluate the n-th roots, then we need to evaluate the integral powers, and then we can reach at our desired result.

The conversion is as follows -

`(x^3y^4)^{(2)/(3)}\\\\=\sqrt[3]{(x^3y^4)^2}\\\\ =\sqrt[3]{x^6y^8}\\\\=x^{(6)/(3)}y^{(8)/(3)}\\\\=x^2y^{2+(2)/(3)}\\\\=x^2y^2y^(2)/(3)\\\\=x^2y^2\sqrt[3]{y^2}.`

Thus, the answer is

`x^2y^2\sqrt[3]{y^2}.`