Question

Pls help meeeee!!!! 3^5x-9= (1/27)^2x-8 for x. I alo put ia picture

Answer 1

x = 3

Explanation:

3^(5x - 9) = (1/27)^(2x-8)

3^(5x - 9) =(3^-3)^(2x-8)

3^(5x - 9) = 3^(-6x + 24)

So now you can solve for x since you have same base 3

5x - 9 = -6x + 24

11x = 33

x = 3

Answer 2

x=3

Explanation:

3^5x-9= (1/27)^2x-8

Replace 1/27 = 1/3^3 = 3^-3

3^5x-9= (3^-3)^2x-8

a^b^c = a^(b*c)

3^5x-9= 3^(-3)*2x-8

Distribute

3^5x-9= 3^-6x+24

Since the bases are the same, the exponents are the same

a^b = a^c means b=c

5x-9= -6x+24

Add 6x to each side

5x+6x-9= -6x+6x+24

11x-9 = 24

Add 9 to each side

11x+9-9 = 24+9

11x = 33

Divide by 11

11x/11 = 33/11

x = 3