Question

What is the standard form equation of the line shown below? (1 point)

Graph of a line going through negative 3, negative 1 and 3, 2


y + 1 = one half(x + 3)

y = one halfx + five halves

−x + 2y = 1

x − 2y = −1

Answer 1

Option D, "x − 2y = −1" is the correct answer.

Explanation:

I just finished the test.

Answer 2

x-2y=-1

Explanation:

To write the equation of a line we must have a slope and a point. To find the slope we use the slope formula and substitute (x,y) points in it as shown below:

`m=(y_2-y_1)/(x_2-x_1)=(2--1)/(3--3)=(2+1)/(3+3)=(3)/(6)=(1)/(2)`

Now that we have the slope, plug in the slope and choose one point to plug into the point slope formula. Use the point-slope form to write the equation, then simplify and convert into the slope intercept form.

(y--1)=1/2(x--3)

y+1=1/2(x+3)

y+1=1/2x+3/2

y=1/2x + 1/2

Now convert to standard form, Ax+By=C.

y=1/2x + 1/2

2y = x +1

-x+2y+1 (multiply by -1 since A cannot be negative)

x-2y=-1