Question

How much heat will be absorbed by a 66.3 g

piece of aluminum (specific heat = 0.930 J/
g. °C) as it changes temperature from 23.0°C
to 67.0°C?

Answer 1

Q=mcΔt

Q=66.3 x 0.93 x (67-23)

Q=2712.996 J

Answer 2

`\quad \huge \quad \quad \boxed{ \tt \:Answer }`

`\qquad \tt \rightarrow \:Q = 2.713 \:\:kJ`

____________________________________

`\large \tt Solution \: :`

`\qquad \tt \rightarrow \: Q = ms\Delta T`

`\textsf{Q = heat evolved/absorbed = ??}`

`\textsf{m = mass in gram = 66.3 g}`

`\textsf{s = specific heat = 0.930 J/g °C}`

`\textsf{ΔT = change in temp = 67 - 23 =44°C}`

`\large\textsf{Find Q : }`

`\qquad \tt \rightarrow \:Q=( 66.3) \sdot (0.93) \sdot(44)`

`\qquad \tt \rightarrow \:Q = 2713 \: \: joules`

`\qquad \tt \rightarrow \:Q= 2.713 \: \: kj`

Answered by : ❝ AǫᴜᴀWɪᴢ ❞