375,103 views
43 votes
43 votes
How much heat will be absorbed by a 66.3 g

piece of aluminum (specific heat = 0.930 J/
g. °C) as it changes temperature from 23.0°C
to 67.0°C?

User Ben Wilhelm
by
3.2k points

2 Answers

20 votes
20 votes

Q=mcΔt

Q=66.3 x 0.93 x (67-23)

Q=2712.996 J

User Maerics
by
3.7k points
19 votes
19 votes


\quad \huge \quad \quad \boxed{ \tt \:Answer }


\qquad \tt \rightarrow \:Q = 2.713 \:\:kJ

____________________________________


\large \tt Solution \: :


\qquad \tt \rightarrow \: Q = ms\Delta T


\textsf{Q = heat evolved/absorbed = ??}


\textsf{m = mass in gram = 66.3 g}


\textsf{s = specific heat = 0.930 J/g °C}


\textsf{ΔT = change in temp = 67 - 23 =44°C}


\large\textsf{Find Q : }


\qquad \tt \rightarrow \:Q=( 66.3) \sdot (0.93) \sdot(44)


\qquad \tt \rightarrow \:Q = 2713 \: \: joules


\qquad \tt \rightarrow \:Q= 2.713 \: \: kj

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

User Vstepaniuk
by
3.2k points