Question

What would x be? (giving 50 points!)
Using the following image, solve for x.

Answer 1

`\huge \boxed{\sf x=-3}\\\\\\\displaystyle \sf CD+DE=8 \\\\x+10+x+4=8\\\\2x+14=8\\\\Subtracting\ 14\ from\ each\ side\\\\ 2x+14-14=8-14\\\\2x=-6\\\\ Dividing\ each\ side\ by\ 2 \\\\ (2x)/(2) =(-6)/(2) \\\\x=-3`

Answer 2

`\quad \huge \quad \quad \boxed{ \tt \:Answer }`

`\qquad \tt \rightarrow \:x = -3`

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`\large \tt Solution \: :`

`\qquad \tt \rightarrow \: CD + DE = CE`

`\qquad \tt \rightarrow \: x + 10 + x + 4 = 8`

`\qquad \tt \rightarrow \: 2x + 14 = 8`

`\qquad \tt \rightarrow \: 2x =8 - 14`

`\qquad \tt \rightarrow \: 2x = - 6`

`\qquad \tt \rightarrow \: x = - 3`

Answered by : ❝ AǫᴜᴀWɪᴢ ❞