Question

In one season marty, carlos, andrew hit a total of 108 home runs. Marty and andrew together hit twice as many home runs as did carlos although carlos had one more home run than andrew. How many home runs did each player hit?

Answer 1

Let M represents the Marty , C represents the Carlos and A represents the Andrew.

As per the given statement:

In one season Marty, Carlos, Andrew hit a total of 108 home runs

⇒
`M+C+A = 108` ......[1]

It is also given that Marty and Andrew together hit twice as many home runs as did Carlos,

⇒
`M+A = 2C` ......[2]

Also, Carlos had one more home run than Andrew.

⇒
`C = A+1` .....[3]

Substitute equation [2] into [1] we get;

`2C+ C = 108`

Combine like terms;

`3C = 108`

Divide both sides by 3 we get;

C = 36 hit home runs

Substitute the value of C in [3] we have;

`36 = A + 1`

Subtract 1 from both sides we get;

A = 35 hit home runs

Substitute the value of A and C in [1] we have;

`M+36+35 = 108`

or

`M+71 = 108`

Subtract 71 from both sides we get;

`M = 37` hit home runs.

Therefore, each player hit:

Carlos = 36 hit home runs

Andrew = 35 hit home runs

And

Marty = 37 hit home runs.

Answer 2

Carlos hit 36 runs

Marty hits 37 home runs

Andrew hit 35 home runs

Explanation:

Given :

Let M represents the Marty , C represents the Carlos and A represents the Andrew.

Now we are given that In one season Marty, Carlos, Andrew hit a total of 108 home run

⇒ M+C+A=108 --a

we are also given that Marty and Andrew together hit twice as many home runs as did Carlos,

⇒M+A=2C ---b

Also, Carlos had one more home run than Andrew.

⇒C=1+A --c

Now put equation b in a

⇒2C+C=108

⇒3C=108

⇒C=108/3

⇒C=36

Thus Carlos hit 36 runs

Put value of C in equation c

⇒ 36=A+1

⇒35=A

Thus Andrew hit 35 home runs

Now put values of A and C in equation a to get value of M

M+36+35=108

M+71=108

M=108-71=37

Thus Marty hits 37 home runs

Hence Carlos hit 36 runs

Marty hits 37 home runs

Andrew hit 35 home runs