Question

Y= 9x + 7 over 3 rewrite in standard form

Answer 1

subtract 9x from its side and move it over, -9x+y=7/3 should be your answer, hope i helped

Answer 2

`3x-1y=-(7)/(3)`

Explanation:

We've been given the equation
`y=(9x+7)/(3)`

In order to bring it in the standard form we must write it as Ax + By = C

First, we need to split and divide both the terms of the numerator by 3 on the right side

`y=(9x)/(3)+(7)/(3)`

Simplifying
`(9)/(3)`, we get 3

`y=3x+(7)/(3)`

Subtract
`(7)/(3)` from both side

`y-(7)/(3)=3x+(7)/(3)-(7)/(3)`

Cancel out
`+(7)/(3)` and
`-(7)/(3)` from the right side

`y-(7)/(3)=3x`

Subtract y from both sides

`y-(7)/(3)-y=3x-y`

Cancel out y and -y on the left side

`-(7)/(3)=3x-y`

y is written as 1y

`-(7)/(3)=3x-1y`

Flip the sides

`3x-1y=-(7)/(3)`