13) phosphoric acid + potassium hydroxide
H3PO4 + 3 KOH ------------> K3PO4 + 3H2O
H3PO4 ( acid )
KOH ( base )
K3PO4 ( salt )
Therefore fore K3PO4 is salt ( tripotassium phosfate )
14) Al(ClO4)3
Al⁺³ ClO₄⁻
in chlorine = x + ( - 2 * 4 ) = -1
x - 8 +1 = 0
x = 8 - 1
x = +7
in Al(ClO4)3 chlorine oxidation state + 7
15) CuO(s) + H2 (g) Cu(s) + H2O (l)
The oxidation state of Cu in CuO = +2
The oxidation state of H in H2 = 0
The oxidation state of Cu in Cu = 0
The oxidation state of H in H2O = +1
That in the above reaction , The oxidation state of Cu is decreased from +2 to 0 , so Cu⁺² is reduced , The oxidation state of H is decreased from 0 to +1 , So H2 is oxidized .
Hope that helps!