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The second side of a triangular deck is 5 feet longer than the shortest side. The third side of the deck is 5 feet shorter than twice the length of the shortest side. If the perimeter of the deck is 72 ​feet, what are the lengths of the three​ sides?

1 Answer

5 votes

Answer:

  • 18 ft
  • 23 ft
  • 31 ft

Explanation:

Let s represent the length of the shortest side in feet. Then the second side is repreesented by s+5, and the third side by 2s-5. The perimeter is the sum of these side lengths:

... 72 = (s) + (s+5) + (2s-5)

... 72 = 4s . . . . . . to find s, we must divide this by 4

... 18 = s . . . . length in feet of the shortest side

The second side is ...

... s+5 = 18+5 = 23 . . . . feet

The third side is ...

... 2s-5 = 2·18 -5 = 31 . . . . feet

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