Answer:
1000 Joules per second.
Step-by-step explanation:
To lift that much grass 5 meters higher than it was before the tractor did work that is the product of the (force needed to overdo gravity) and (displacement):
![W = mg\Delta h=120kg\cdot 10(m)/(s^2)\cdot 5m = 6000J](https://img.qammunity.org/2020/formulas/physics/middle-school/6a47ygiuvp2appz04i21houp6lg3rcip2o.png)
Power is work over the amount of time:
![P = (W)/(\Delta t)=(6000J)/(6 s) = 1000 (J)/(s)](https://img.qammunity.org/2020/formulas/physics/middle-school/8iyam1w5esjzq1amj1tc3csp8l1ta6c5pc.png)