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Write the following equation in standard form then solve. 6q^2-2q=5q^2-5q+28

Write the following equation in standard form then solve. 6q^2-2q=5q^2-5q+28-example-1

1 Answer

3 votes

Answer:

q = -7, q = 4

Explanation:

subtract 5q² - 5q + 28 from both sides to obtain standard form

q² + 3q - 28 = 0 ← in standard form

(q + 7)(q - 4) = 0 ← in factored form

equate each factor to zero and solve for q

q + 7 = 0 ⇒ q = - 7

q - 4 = 0 ⇒ q = 4


User Mike Stay
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