Question

If a rocket powered sled is accelerated to a speed of 444 m/s in 1.83 seconds then what is the acceleration and what is the distance that the sled travels?

Answer 1

1. Acceleration: 242.6 m/s^2

Step-by-step explanation:

The acceleration of the sled is given by:

`a=(v-u)/(t)`

where

v is the final velocity

u is the initial velocity

t is the time taken for the sled to accelerate from u to v

For the sled in the problem, we have:

u = 0 m/s

v = 444 m/s

t = 1.83 s

Therefore, its acceleration is

`a=(444 m/s-0 m/s)/(1.83 s)=242.6 m/s^2`

2. Distance travelled by the sled: 406.3 m

Step-by-step explanation:

We can solve this part of the problem by using the following SUVAT equation:

`v^2 - u^2 = 2ad`

where d is the distance travelled by the sled.

By using v = 444 m/s, u = 0 m/s, and a = 242.6 m/s^2, we can re-arrange the equation and find d:

`d=(v^2-u^2)/(2a)=((444 m/s)^2-(0 m/s)^2)/(2(242.6 m/s^2))=406.3 m`