What is the minimum allowed length for the runway?

asked Nov 12, 2020 72.5k views

1 vote

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4 votes

v = u + a t => t = v/a = 65/3 sec

s = u t + 1/2 a t² = 1/2 * 3 * 65²/3² = 704.6 meters

hop it helps

Liorr answered Nov 17, 2020

by Liorr

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