Question

Which of the following changes would double the force between two charged particles? O A. Decreasing the distance between the particles by a factor of 2 B. Increasing the distance between the particles by a factor of 2 O C. Doubling the amount of charge on one of the particles O D. Doubling the amount of charge on each particle

Answer 1

Let's check

`\\ \rm\dashrightarrow F=(k)/(q_1q_2){r^2}`

`\\ \rm\dashrightarrow F\propto Q`

`\\ \rm\dashrightarrow F\propto (1)/(r^2)`

So

Option A and C can be used

Answer 2

Decreasing the distance between the particles by a factor of 2

Step-by-step explanation:

To double the force between the two charge particles, the distance between the particles should be reduced by a factor of two.

According to coulombs law "force is directly proportional to the potential between the two charges and inversely proportional to the square of their distances".

`\sf{F  = (kq_(1) q_(2) )/(r^(2) )}`

F is the electric force

k is the coulomb constant

q is the charge

r is the distance or separation

As the separation between the charges is reduced the force increases and vice versa.