Question

Factor by grouping.....

Answer 1

A.
`(4x^(2)+1)(3x+1 )`

Explanation:

The following lines will show the process of factorization by using common factor.

Line 1:

In line 1, we group terms from which the common terms will be factored out.

`12x^(3)+4x^(2)+3x+1=0`

`(12x^(3)+4x^(2) )+(3x+1)=0`

Line 2:

In line 2, we find the common terms from both groups.
`4x^(2)` is the common term in group 1 and 1 is common for group 2.

`4x^(2)(3x+1 )+1(3x+1)=0`

Now we take out the common term from whole equation which is 3x+1.This leaves us with equation as follows:

`(3x+1 )(4x^(2)+1)=0`

which is option A.

So option A.
`(4x^(2)+1)(3x+1 )` is the correct answer.