Question

3. Write an equation for the line perpendicular to y = 6x - 5 that contains (2, 10)

Answer 1

`y = -(1)/(6)x +(31)/(3)`

Explanation:

We are to find the equation for the line which is perpendicular to another line with the equation
`y = 6x - 5` and passes through a point (2, 10).

Since the slope of a line which is perpendicular to another line is the negative reciprocal of the other line, therefore the slope of our line will be
`-(1)/(6)`.

Finding the y-intercept:

`y=mx+c`

`10=-(1)/(6) (2)+c`

`c=(31)/(3)`

Therefore, the equation of the line will be
`y = -(1)/(6)x +(31)/(3)`.