Question

The perimeter of a basketball court is 266 ft, and its length is 35 ft more than its width. Find the dimensions of the court.

Answer 1

Hello there,

The perimeter of a basketball court is 266 ft, and its length is 35 ft more than its width. Find the dimensions of the court.

Answer: w = 49 ft and l = 84ft

266 = 2(35+x+x)

266/2=35+2x

133=35+2x

133-35=35-35+2x

98=2x

98/2=2x/2

49=x

We already know the length is 35, so

=35+x

=35+49=84ft

Answer 2

w = 49 ft and l = 84ft

Explanation:

P = 266

The formula for perimeter = 2(l+w)

We know the length is 35 more than the width

l = w+35

Substituting in for Perimeter

266 =2(l+w)

Now replacing l with w+35

266 =2(w+35+w)

Combine like terms

266 = 2(2w+35)

Divide each side by 2

266/2 = 2/2 (2w+35)

133 = 2w+35

Subtract 35 from each side

133-35 = 2w+35-35

98 = 2w

Divide by 2

98/2 = 2w/2

49 =w

We still need to find l

l = w +35

l = 49+35

l = 84