136k views
0 votes
During the first hour of operation the farm stand owner sold 15% of the apples he had. On the second hour he sold 20% of the remaining apples. On the third hour he sold 25% of the remaining apples, and so on, selling 5% more each following hour. If during the third hour he sold 34 kg of apples, how many kilograms of apples did he have initially?

User Jamus
by
8.2k points

1 Answer

4 votes

Answer:

Initially he had 200 kg of apples.

Explanation:

Let x kg be the amount of apples the farm stand initially had.

During the first hour of operation the farm stand owner sold 15% of the apples he had, then he sold
0.15x kg of apples and
x-0.15x=0.85x kg of apples left.

On the second hour he sold 20% of the remaining apples, then he sold
0.20\cdot 0.85x=0.17x kg of apples and
0.85x-0.17x=0.68x kg of apples left.

On the third hour he sold 25% of the remaining apples, then during the third hour he sold
0.25\cdot 0.68x=0.17x kg of apples.

If during the third hour he sold 34 kg of apples, then
0.17x=34\Rightarrow x=(34)/(0.17)=200\ kg.

No related questions found