Question

Write the following equation in standard form. Then solve. 4q^2+2q=3q^2-4q+16

Answer 1

The Correct Answer is q^2+5q-14=0

Explanation:

Answer 2

`4q^2+2q=3q^2-4q+16\qquad\text{subtract}\ 3q^2\ \text{from both sides}\\\\q^2+2q=-4q+16\qquad\text{add}\ 4q\ \text{to both sides}\\\\q^2+6q=16\qquad\text{subtract 16 from both sides}\\\\q^2+6q-16=0\to\boxed{\text{standard form}}\\\\q^2+8q-2q-16=0\\\\q(q+8)-2(q+8)=0\\\\(q+8)(q-2)=0\iff q+8=0\ \vee\ q-2=0\\\\q+8=0\qquad\text{subtract 8 from both sides}\\\\\boxed{q=-8}\\\\q-2=0\qquad\text{add 2 to both sides}\\\\\boxed{q=2}\\\\Answer:\ \boxed{q=-8\ or\ q=2}`