233k views
3 votes
What is the polynomial function of lowest degree with lead coefficent 1 and roots i, -2, 2?

User Eirirlar
by
6.5k points

1 Answer

1 vote

Answer:


x^(4) - 3x² - 4

Explanation:

given the roots of a polynomial, say x = a, x = b and x = c

Then the factors of the polynomial are (x - a), (x - b) and (x - c)

and f(x) = a(x - a)(x - b)(x - c) ← a is a multiplier

Note that complex roots occur in conjugate pairs

hence x = i is a root then x = - i is also a root

the roots are x = - 2, x = 2, x = i and x = - i

factors are (x + 2)(x - 2)(x - i)(x + i) ← expand in pairs

f(x) = (x² - 4)(x² - i²) → (i² = - 1 )

= (x² - 4(x² + 1)

=
x^(4) - 4x² + x² - 4 ← collect like terms

=
x^(4) - 3x² - 4


User Randomeister
by
7.1k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.